Model 6  Efficiency of the worker Practice Questions Answers Test with Solutions & More Shortcuts

Question : 26 [SSC FCI Assistant Grade-III 2012]

A can do a piece of work in 70 days and B is 40% more efficient than A. The number of days taken by B to do the same work is

a) 45 days

b) 40 days

c) 60 days

d) 50 days

Answer: (d)

A : B = $D_2 : D_1$

100 : 140 = $D_2$ : 70

100 × 70 = 140 × $D_2$

$D_2 = {100 × 70}/140 = 50$ days.

Using Rule 17
If A can do a work in 'x' days and B is R% more efficient than A, then 'B' alone will do the same work in $x × 100/{100 + R}$ days

Here, x = 70, r = 40%

Time taken by B = $x × 100/{100 + R}$

= ${70 × 100}/{100 + 40}$ = 50 days

Question : 27 [SSC CPO S.I.2006]

Kamal can do a work in 15 days. Bimal is 50 per cent more efficient than Kamal in doing the work. In how many days will Bimal do that work?

a) 10$1/2$ days

b) 14 days

c) 12 days

d) 10 days

Answer: (d)

Using Rule 15
The comparison of rate of work done is called efficiency of doing work. Efficiency (E) ∝ $1/\text"No. of days"$ E1 : E2 : E3 = $1/D_1 : 1/D_2 : 1/D_3$, E =$k/D$ or, ED =k or, $E_1D_1= E_2D_2$

Efficiency and time taken are inversely proportional Bimal : Kamal = 150 : 100 (work)

100 : 150 (Time) = 2 : 3

Since, 3 units ⇒ 15 days

2 units ⇒ $15/3 × 2$ = 10

Hence, Bimal complete the work in 10 days

Question : 28 [SSC CHSL 2012]

A is thrice as good a workman as B and is, therefore, able to finish a piece of work in 60 days less than B. The time (in days) in which they can do it working together is

a) 23$1/4$ days

b) 22 days

c) 22$1/2$ days

d) 23 days

Answer: (c)

Using Rule 2,

If A completes the work in x days,

B will do the same in 3x days.

3x - x = 60

2x = 60

x = 30 and 3x = 90

(A + B)’s 1 day’s work

= $1/30 + 1/90 = {3 + 1}/90$

= $4/90 = 2/45$

A and B together will do the work in $45/2$ or 22$1/2$ days.

Question : 29 [SSC CGL Prelim 2003]

Babu and Asha can do a job together in 7 days. Asha is 1$3/4$ times as efficient as Babu. The same job can be done by Asha alone in

a) $28/3$ days

b) $49/4$ days

c) $49/3$ days

d) 11 days

Answer: (d)

Ratio of efficiency of Babu and Asha

= 1 : $7/4$ = 4 : 7.

As the time taken is inversely proportional to efficiency, therefore, if Babu takes 7x days to complete work, Asha will take 4x days.

$1/{7x} + 1/{4x} = 1/7 ⇒ {4 + 7}/{28x} = 1/7$

28x = 11 × 7

$x = {11 × 7}/28 = 11/4$

Asha will complete the work in

$4x = 4 × 11/4$ = 11 days.

Using Rule 22,

Here, n = $7/4$, D = 7

Time taken by Asha= $({n + 1}/n)$D days

= $({{7/4} + 1}/{7/4}) × 7 = 11/7 × 7$ = 11 days

Question : 30 [SSC CGL Tier-II 2013]

Sunil completes a work in 4 days, whereas Dinesh completes the work in 6 days. Ramesh works 1$1/2$ times as fast as Sunil. The three together can complete the work in

a) 1$5/19$ days

b) 1$5/12$ days

c) 1$5/7$ days

d) 1$3/8$ days

Answer: (a)

Using Rule 3
If A can do a work in 'x' days, B can do the same work in 'y' days, C can do the same work in 'z' days then, total time taken by A, B and C to complete the work together = $1/{1/x + 1/y + 1/z} = {xyz}/{xy + yz + zx}$and
If workers are more than 3 then total time taken by A, B, C ...... so on to complete the work together = $1/{1/x + 1/y + 1/z + ...}$

Time taken by Ramesh

= $4 × 2/3 = 8/3$ days

Work done by all three in 1 day

= $1/4 + 1/6 + 3/8 = {6 + 4 + 9}/24 = 19/24$

Required time

= $24/19 = 1{5}/19$ days

IMPORTANT quantitative aptitude EXERCISES

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